leetcode(3) Jewels and Stones

difficult:easy #771

You’re given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so “a” is considered a different type of stone from “A”.
Example 1:

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Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:
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Input: J = "z", S = "ZZ"
Output: 0

Note:
S and J will consist of letters and have length at most 50.
The characters in J are distinct.

解法

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#include<string>
int numJewelsInStones(std::string J, std::string S) {
int num = 0;
for (auto i = S.begin(); i < S.end(); i++) {
if (J.find(*i) != std::string::npos)
num++;
}
return num;
}

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leetcode(3) Jewels and Stones
https://jiaopaner.github.io/2018/07/08/leetcode(3) Jewels and Stones/
作者
JiaoPan
发布于
2018年7月8日
许可协议